文件路径拆分(分解)
By
admin
at 2017-12-10 • 1人收藏 • 1809人看过
import console;
path = io.splitpath("z:\编辑部\==连版==\已经照排过的版面\old\9-6-51.ps")
io.open()
io.print("驱动器",path.drive)
io.print("目录",path.dir)
io.print("文件名",path.name)
io.print("后缀名",path.ext)
io.print("文件名+后缀名",path.file);
console.pause(true);
3 个回复 | 最后更新于 2018-02-06
admin
2018-01-05
#1

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